Since each card handling takes a minimum amount of time, say, 1/10 of a second, and a maximum amount of time, say 10 seconds, then since
¼n2 ≤ H(n) ≤ 2n2
We have:
1⁄40n2 ≤ T(n) ≤ 20n2
Since T(n) is also between multiples of n2, we say
T(n) = Θ(n2)
Both the number of handlings and the time taken is Θ(n2).
n2 tells the general shape or order of growth of both H(n) and T(n).