Solve a similar, slightly smaller problem first and do a little work on the result.
This approach is called linear recursion.
Example:
(define factorial
(lambda (n)
(if (= n 1)
1
(* (factorial (- n 1))
n))))
(factorial 4)
\
\
(* 4 (factorial 3))
\
\
(* 3 (factorial 2)
\
\
(* 2 (factorial 1))
/
/
(* 2 1) => 2
/
/
(* 3 2) => 6
/
/
(* 4 6) => 24